#### Details of this Paper

##### 1. A sample of 50 golfers showed that their averag...

**Description**

Solution

**Question**

1. A sample of 50 golfers showed that their average score on a particular golf course was 90 with a standard deviation of 10. Answer each of the following (show all work): (A) Find the 99% confidence interval of the mean score for all 50 golfers. (B) Find the 99% confidence interval of the mean score for all golfers if this is a sample of 80 golfers instead of a sample of 50. (C) Which confidence interval is larger and why? 2. Consider the sample data below. 34 21 23 52 34 38 36 49 36 34 20 50 44 36 43 27 45 40 52 39 31 54 20 30 34 50 40 25 26 27 26 21 43 Suppose we wish to test the following hypotheses for the data: H0 : ? 40 Ha : > 40 Calculate the mean (x-bar) and the standard deviation s of the data as above: (A) Compute the appropriate test statistic for testing H0 (show all work). (B) Determine the critical value for a = 0.05. (C) Test H0 using the traditional/classical method. (D) State the decision based on the results of the test. (E) Had you used the p-value method of hypothesis testing, what would the p-value have been? 3. A researcher is interested in estimating the noise levels in decibels at area urban hospitals. She wants to be 95% confident that her estimate is correct. If the standard deviation is 4.8, how large a sample is needed to get the desired information to be accurate within 0.60 decibels? Show all work. 4. A sample size of 50 is used to test H0 : ? ? 60 vs. Ha : ? 12 , ? = 0.10 (C) H0 : ? ? 18 and Ha : ? < 18 , ? = 0.01 9. A 95% confidence interval estimate for a population mean was computed to be (44.8 to 50.2). Determine the mean of the sample, which was used to determine the interval estimate (show all work). 10. In testing the hypothesis, H0 :? ? 31.5 and Ha : ? < ? < 79 So if this is how you templated it lets go.

Paper#13359 | Written in 18-Jul-2015

Price :*$25*