Description of this paper

For the half reaction: Pb^4+(aq)+2e- = Pb^2+

Description

solution


Question

a)For the half reaction: Pb^4+(aq)+2e- = Pb^2+;Calculate the cell voltage E, at 25C if the concentration of Pb^4+ is 0.5M and that of Pb^2+ is 0.1M;b)Calculate delta G (in kJ) for the reaction: Cd+Pb^2+=Cd^2+ + Pb;Potential, E, of the cell is measured at 0.29V;Additional Requirements;Level of Detail: Show all work

 

Paper#15827 | Written in 18-Jul-2015

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