Details of this Paper

A diploid cell contains three pairs of homologous..

Description

solution


Question

SC435_Assignment1_Unit_4 (1).docx Download Attachment;SC435: Genetics;SC435 Unit 4 Assignment 75 points;1. (6 points) A diploid cell contains three pairs of homologous chromosomes;designated C1 and C2, M1 and M2, and S1 and S2. No crossing over occurs.;a. What combination(s) of chromosomes are possible in daughter cells following;mitosis?;In mitosis, two genetically identical daughter cells are produced. Therefore, the;only possible combination of chromosomes is C1/C2/M1/M2/S1/S2 since all;genetic material is inherited.;b. What combination(s) of chromosomes are possible in haploid cells following;both divisions of meiosis? (Hint: remember independent assortment);C1/M1/S1, C1/M1/S2, C2/M1/S1, C1/M2/S1, C1/M2/S2, C2/M1/S1, C2/M2/S1;or C2/M2/S2.;2. (15 points) A recessive mutant allele, black, causes a very dark body in;Drosophila when homozygous. The normal wild-type color is gray.;a. A black female is crossed to a heterozygous gray male. What are the parental;genotypes?;b. What F1 phenotypic and genotypic ratios are produced from this cross? (Show;your Punnett Square);3. (9 points) R codes for red flower color and r codes for white flower color.;a. What color would Rr be if R has complete dominance?;b. What color would Rr be if R and r are codominant?;c. What color would Rr be if R has incomplete dominance?;4. (15 points) Red-green colorblindness is an X-linked recessive mutation. A;colorblind female is crossed with a normal male.;a. What are the parental genotypes? (Hint: the sex of the parent is important);SC435: Genetics;b. Diagram the F1 results from this cross. (Show your Punnett Square).;c. Diagram the F2 results. (Show your Punnett Square).;5.;(5 points) In a dihybrid cross between RrTt and RRtt, what are the genotype;and phenotype ratios of the offspring, assuming R and T are dominant? R;codes for round seed, while r codes for wrinkled seed. T codes for tall height;while t codes for short height. (Show your Punnett Square).;6. (15 points) The pedigree below traces the inheritance of alkaptonuria, a;biochemical disorder. Affected individuals, indicated here by the filled-in circles;and squares, are unable to break down a substance called alkapton, which;colors the urine and stains body tissues.;a. Does alkaptonuria appear to be caused by a dominant or recessive allele?;Explain.;Alkaptonuria appears to be caused by a recessive allele because Ann and;Michael do not have the disorder but their child, Carla, does. Ann and;Michael must be carrying the recessive allele but it is masked by the;dominant one;b. What is Georges phenotype?;George is Aa, since some of his children with Arlene are affected;c. Is it possible for Daniel to have a child with alkaptonuria? Explain.;Yes Christopher can have the AA or Aa genotype.;SC435: Genetics;d. How would knowing the pattern of inheritance influence the treatment plan;for this disease?;It would provide guidance to determine if genetic testing is appropriate.;7. (10 points) Mary has type A blood and her husband has type B blood. Her;husbands parents both had type AB. They have three children, one with type A;one with type AB, and one with type B. Relatives suspect that one of the children;was adopted.;a. What are the parents blood genotypes?;b. Which child was adopted? Explain your answer.

 

Paper#18139 | Written in 18-Jul-2015

Price : $37
SiteLock