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Calculate the upper value (limit) for the interval estimate of the difference between the proportions of

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Calculate the upper value (limit) for the interval estimate of the difference between the proportions of two populations where 286 in a sample of 2,118 from the first population exhibited the characteristic of interest and 251 in a sample of 2,682 from the second population exhibited the characteristic of interest. Use alpha=0.02. Use Excel's "normsinv" function to calculate the critical value of z.;Please input in excel so that I can see the way the correct answer is found. You had given me the answer of;Solution;We have alpha = 0.02, then alpha/2 = 0.01;Using = normsinv (0.01), the critical value is 2.326;We find the common proportion first.;P = (X1 + X2)/ (n1 + n2);= (286 + 251)/ (2118 + 2682);= 0.1119;p?1 = X1/n1;= 286/2118;= 0.135;p?2 = X2/n2;= 251/2682;= 0.0936;Upper limit is calculated by:-;(p?1- p?2) + Z?/2 *?((p(1-p))/n1+(p (1-p))/n2);(0.135-0.0936) + 2.326 *?((0.1119(1-0.1119))/2118+(0.1119 (1-0.1119))/2682);0.0414 + 2.326*0.0079;0.0414 + 0.0183;0.0597;I just can't seem to get the same answer as you have. Thank You

 

Paper#31858 | Written in 18-Jul-2015

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