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Question;[1] In March 16, 1998, issue of Fortune magazine;the results of a survey of 2,221 MBA students from across the United States;conducted by the Stockholm-based academic consulting firm Universum showed that;only 20 percent of MBA students expect to stay at their first job five years or;more. Source: Shalley Branch;MBAs: What Do They Really Want," Fortune (March 16, 1998), p.167.;a);Assuming;that a random sample was selected, construct a 98% confidence interval for the;proportion of all U.S. MBA students who expect to stay at their first job five;years or more.;b);Based;on the interval from a), can you conclude that there is strong evidence that;less than one-fourth of all U.S. MBA students expect to stay? Explain why.;[2];An earlier study claims that U.S.;adults spend an average of 114 minutes with their families per day. A recently taken sample of 25 adults showed;that they spend an average of 109 minutes per day with their families. The sample standard deviation is 11;minutes. Assume that the time spent by;adults with their families has an approximate normal distribution. We wish to;test whether the mean time spent currently by all adults with their families is;less than 114 minutes a day.;a);Construct;a 95% confidence interval for the mean time spent by all adults with their;families.;b);Does;the sample information support that the mean time spent currently by all adults;with their families is less than 114 minutes a day? Explain your conclusion in words.;[3];In the case of Casteneda v. Partida;it was found that during a period of 11 years in Hilda County, Texas, 870;people were selected for grand jury duty, and 39% of them were Americans of;Mexican ancestry. Among the people;eligible for grand jury duty, 79.1% were Americans of Mexican ancestry. We shall use a 0.01 significance level to;test the claim that the selection process is biased against Americans of;Mexican ancestry.;a);Set;up the null and alternative hypotheses, and perform the hypothesis test.;b);Does;the jury selection system appear to be fair?;[4];When 40 people used the Weight Watchers diet for one year, their mean weight;loss was 3.00 lb.;(based on data from ?Comparison of the Atkins, Ornish, Weight Watchers, and;Zone Diets for Weight Loss and Heart Disease Reduction,? by Dansinger, et al., Journal of the American Medical Association;Vol. 293, No. 1). Assume that the;standard deviation of all such weight changes iss = 4.9 lb. We shall use a 0.01 significance level to;test the claim that the mean weight loss is greater than 0.;a);Set;up the null and alternative hypotheses, and perform the hypothesis test.;b);Based;on these results, does the diet appear to be effective? Does the diet appear to have practical;significance?;[5];A local television station has added a consumer spot to its nightly news. The consumer reporter has recently bought sixteen;bottles of aspirin from a local drugstore and has counted the aspirins in each;bottle. Although the bottles advertised 500;aspirins, the reporter found the following numbers with the mean count;498.8125;499, 498, 496, 501, 493, 495, 497, 502, 496;502, 499, 501, 500, 498, 501, 503;The;consumer reporter claims that this is an obvious case of the public being taken;advantage of. Using a confidence;interval estimate method or a hypothesis testing method, do you think that the reporter?s;claim is justifiable?


Paper#52635 | Written in 18-Jul-2015

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