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MGSC 625 Problem 15-14

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solution


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Question;Unformatted Question, please see the attachement for the original question MGSC 625 Problem 15-14 15-24 Case 2.4, Case;3-1;Problem;15-14;Period;1;2;3;4;5;Demand;20;40;30;10;45;Co = 100 per order;Avg. demand/period, d=;29;Cc = $1 per unit per cabinet period;L4L;Rule Used.;Item X;LLC;Periods;Periods;L4L;LT =1;1;2;3;4;5;Gross;Requirements;20;40;30;10;45;Scheduled;Receipts;0;0;0;0;0;Projected on;hand--25;5;0;0;0;0;Net;requirements;0;35;30;10;45;Planned order;receipts;35;30;10;45;Planned order;releases;35;30;10;45;Cost of L4L;$ 310.00;Ordering + Carrying;Cost;EOQ;Lot sizing;Item X;LLC;Periods;Periods;EOQ;LT =1;1;2;3;4;5;Gross;Requirements;20;40;30;10;45;Scheduled;Receipts;0;Projected on;hand--25;5;41;11;1;32;Net;requirements;0;35;0;10;44;Planned order;receipts;76;0;76;Planned order;releases;76;76;0;76;EOQ =;87;Formula;EOQ = SQRT(2*d*Co/Cc);Cost =;$;406.00;POQ Rule.;POQ=;3.00;Rounded to 2. Formula used is EOQ/Avg.;Demand, d.;Produce to take care of two periods;at a time.;Total Planned receipt=;Total gross reqmnts-on-hand=;30;Item X;LLC;Periods;Periods;POQ =2;LT =1;0;1;2;3;4;5;Gross;Requirements;0;20;40;30;10;45;Scheduled;Receipts;Projected on;hand--;25;70;30;0;45;0;Net;requirements;65;0;0;10;0;Planned order;receipts;65;0;55;Planned order;releases;65;55;Planned;order size is the sum of planned order receipt for 2 consecutive weeks.;Cost=;$ 248.00;POQ;lot sizing is the cheapest approach.

 

Paper#53178 | Written in 18-Jul-2015

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