#### Details of this Paper

##### MATH 302 Midterm Exam 2014

Description

solution

Question

Question;Part 1 of 9 -;Question 1 of 25;1.0 Points;The mode is best described as the;A.same as the average;B.middle observation;C.most frequently occurring value;D.50th percentile;Reset Selection;Part 2 of 9 -;Question 2 of 25;1.0 Points;A jar contains four white marbles, five red marbles, and six;black marbles. If a marble is selected at random, find the;probability that it is white or black.;A.2/15;B.2/3;C.1/5;D.2/5;Reset Selection;Question 3 of 25;1.0 Points;The formal way to revise probabilities based on new;information is to use;A.common sense probabilities;B.unilateral probabilities;C.complementary probabilities;D.conditional probabilities;Reset Selection;Part 3 of 9 -;Question 4 of 25;1.0 Points;If a gambler rolls two dice and gets a sum of 10, he wins;\$10, and if he gets a sum of;three, he wins \$20. The cost to play the game is \$5. What is;the expectation of this;game?;A.\$3.06;B.-\$2.78;C.-\$3.06;D.\$2.78;Reset Selection;Question 5 of 25;1.0 Points;Suppose that 50 identical batteries are being tested. After;8 hours of continuous use, assume that a given battery is still;operating with a probability of 0.70 and has failed with a;probability of 0.30.;What is the probability that between 25 and 30 batteries;(inclusive) will last at least 8 hours?;A.0.7792;B.0.1186;C.0.0839;D.0.9169;Reset Selection;Question 6 of 25;1.0 Points;A drug is reported to benefit 40% of the patients who take;it. If 6 patients take the drug, what is the probability that 4 or;more patients will benefit?;A.0.667;B.0.179;C.0.138;D.0.862;Reset Selection;Part 4 of 9 -;Question 7 of 25;1.0 Points;Find the probability, P(Z < 0.17), using the standard;normal distribution.;A..8300;B..4325;C..5675;D..0675;Reset Selection;Question 8 of 25;1.0 Points;Given that Z is a standard normal variable, the value z for;which P(Z < z) = 0.2580 is;A.-0.65;B.-0.70;C.0.242;D.0.758;Reset Selection;Question 9 of 25;1.0 Points;The average height of flowering cherry trees in a nursery is;11 feet. If the heights are;normally distributed with a standard deviation of 1.6, find;the probability that a randomly;selected cherry tree in this nursery is less than 13 feet;tall.;A. 0.67;B.0.89;C.0.95;D.0.11;Reset Selection;Question 10 of 25;1.0 Points;If Z is a standard normal random variable, the area between;z = 0.0 and z =1.30 is 0.4032, while the area between z =;0.0 and z = 1.50 is 0.4332. What is the area between z =;-1.30 and z = 1.50?;A.0.8364;B.0.0668;C.0.0968;D.0.0300;Reset Selection;Question 11 of 25;1.0 Points;Given that the random variable X is normally distributed;with a mean of 80 and a standard deviation of 10, P(85 < X 1.50) =;0.9332;True;False;Reset Selection;1.0 Points

Paper#60648 | Written in 18-Jul-2015

Price : \$27