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##### Seffy MATH STAT 302 FINAL APU - URGENT 3HR TIMED

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Question;Part 1 of 16 -Question 1 of 231.0 PointsThe data presented in the table below resulted from an experiment in which seeds of 5 different types were planted and the number of seeds that germinated within 5 weeks after planting was recorded for each seed type. At the.01 level of significance, is the proportion of seeds that germinate dependent on the seed type?Seed TypeObserved FrequenciesGerminatedFailed to Germinate131725733387604524451019 A.Yes, because the test value 16.86 is greater than the critical value of 13.28 B.Yes, because the test value 16.86 is less than the critical value of 14.86 C.No, because the test value 16.86 is greater than the critical value of 13.28 D.No, because the test value 13.28 is less than the critical value of 16.86Reset SelectionQuestion 2 of 231.0 PointsA company operates four machines during three shifts each day. From production records, the data in the table below were collected. At the.05 level of significance test to determine if the number of breakdowns is independent of the shift.MachineShiftABCD14120121623111914315171610 A.The number of breakdowns is dependent on the shift, because the test value 11.649 is less than the critical value of 12.592. B.The claim that the number of breakdowns is independent of the shift cannot be rejected, because the test value 11.649 is less than the critical value of 12.592. C.The number of breakdowns is dependent on the shift, because the p-value is.07. D.The number of breakdowns is independent of the shift, because the test value 12.592 is greater than the critical value of 11.649.Reset SelectionPart 2 of 16 -Question 3 of 231.0 PointsA single variable X can explain a large percentage of the variation in some other variable Y when the two variables are: A.directly related B.inversely related C.highly correlated D.mutually exclusiveReset SelectionQuestion 4 of 231.0 PointsOutliers are observations that A.lie outside the typical pattern of points B.disrupt the entire linear trend C.lie outside the sample D.render the study uselessReset SelectionQuestion 5 of 231.0 PointsThe marketing manager of a large supermarket chain would like to use shelf space to predict the sales of pet food. For a random sample of 12 similar stores, she gathered the following information regarding the shelf space, in feet, devoted to pet food and the weekly sales in hundreds of dollars..Store123456Shelf Space555101010Weekly Sales1.62.21.41.92.42.6Store789101112Shelf Space151515202020Weekly Sales2.32.72.82.62.93.1Is the correlation between weekly sales and shelf space significant at the.01 level of significance? A.Yes, the computed t-test statistic is less than the critical value. B.Yes, the p-value of the test for significance is less than.01. C.No, the sample correlation coefficient does not exceed the critical value. D.Yes, the value of the test statistic does not exceed the critical value.Reset SelectionPart 3 of 16 -Question 6 of 231.0 PointsSerum ferritin is used in diagnosing iron deficiency. In a study conducted recently researchers discovered that in a sample of 28 elderly men the sample standard deviation of serum ferritin was 52.6 mg/L. For 26 younger men the sample standard deviation was 84.2 mg/L. At the.01 level of significance, do these data support the conclusion that the ferritin distribution in elderly men has a smaller variance than in younger men? A.Yes, because the test value 2.56 is greater than the critical value 0.394 B.Yes, because the test value 0.390 is less than the critical value 2.54 C.No, because the test value 1.60 is less than the critical value of 2.54 D.Yes, because the test value 2.56 is greater than the critical value of 2.54Reset SelectionQuestion 7 of 231.0 PointsQ-Mart is interested in comparing its male and female customers. Q-Mart would like to know if the amount of money spent by its female charge customers differs, on average, from the amount spent by its male charge customers. To answer this question, an analyst collected random samples of 25 female customers and 22 male customers. Based on these samples, on average, the 25 women charge customers spent $102.23 and the 22 men charge customers spent $86.46. Moreover, the sample standard deviation of the amount charged by the 25 women was $93.393, and the sample standard deviation of the amount charged by the 22 men was $59.695. Using the procedure advocated by Bluman, at the 10% level of significance, is there sufficient evidence for Q-Mart to conclude that, on average, the amount spent by women charge customers differs from the amount spent by men charge customers. A.No, the test value does not exceed the critical value. B.Yes, the test value does not exceed the critical value C.No, the p-value of this test is less than 0.10. D.Yes, the p-value of this test is greater than 0.10Reset SelectionPart 4 of 16 -Question 8 of 231.0 PointsIn an article appearing in Today?s Health a writer states that the average number of calories in a serving of popcorn is 75. To determine if the average number of calories in a serving of popcorn is different from 75, a nutritionist selected a random sample of 20 servings of popcorn and computed the sample mean number of calories per serving to be 78 with a sample standard deviation of 7.State the null and alternative hypotheses. A.H0: 75, H1: > 75 B.H0: = 75, H1: > 75 C.H0: 75, H1: < 75 D.H0: = 75, H1:? 75Reset SelectionQuestion 9 of 231.0 Points A lab technician is tested for her consistency by taking multiple measurements of cholesterol levels from the same blood sample. The target accuracy is a variance in measurements of 1.2 or less. If the lab technician takes 16 measurements and the variance of the measurements in the sample is 2.2, does this provide enough evidence to reject the claim that the lab technician?s accuracy is within the target accuracy?At thea =.01 level of significance, what is your conclusion? A.Do not reject H0. At the =.01 level of significance there is not sufficient evidence to suggest that this technician?s true variance is greater than the target accuracy. B. Reject H0. At the =.01 level of significance, there is not enough evidence to support the claim that this technician?s true variance is larger than the target accuracy. C.Reject H0. At the =.01 level of significance, there is enough evidence to support the claim that this technician?s variance is larger than the target accuracy. D.Cannot determineReset SelectionQuestion 10 of 231.0 PointsThe hypothesis that an analyst is trying to prove is called the: A.elective hypothesis B.quality of the researcher C.alternative hypothesis D.level of significanceReset SelectionPart 5 of 16 -Question 11 of 231.0 PointsFind the 95% confidence interval for the standard deviation of the lengths of pipes if a sample of 26 pipes has a standard deviation of 10 inches. A.14.0 < < 16.0 B.7.8 < < 13.8 C.74.0 < < 126.0 D.60.8 < 1500 Sample mean 1509.5 Std error of mean 4.854Assuming the life length of this type of lightbulb is normally distributed, if you wish to conduct this test using a.05 level of significance, what is the critical value that you should use? Place your answer, rounded to 3 decimal places in the blank. For example, 1.234 would be a legitimate entry. Part 16 of 16 -Question 23 of 231.0 PointsAccepted characters: numbers, decimal point markers (period or comma), sign indicators (-), spaces (e.g., as thousands separator, 5 000), "E" or "e" (used in scientific notation). NOTE: For scientific notation, a period MUST be used as the decimal point marker. Complex numbers should be in the form (a + bi) where "a" and "b" need to have explicitly stated values. For example: {1+1i} is valid whereas {1+i} is not. {0+9i} is valid whereas {9i} is not. A probability experiment has two steps. There are two possible results for the first step, call them "A" and "B". If the result for the first step was "A", then there would be 4 possible results for the second step. If the result for the first step was "B", then there would be 16 possible results for the second step. How many possible outcomes are there for this experiment? Place your answer in the blank. Do not use any decimal point or comma. For example, 45 would be a legitimate entry.

Paper#61689 | Written in 18-Jul-2015

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