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Question 1. 1. (TCO 1) The signal is 5 sin (2 pi 2000 t + 60 degrees). The amplitude of this signal is (Points: 5) 5 V PP;3.535 V PP;3.535 V RMS;3.535 V PK;Question 2. 2. (TCO 1) The signal is 5 sin (2 pi 2000 t + 60 degrees). The frequency of this signal is (Points: 5) 2000 Hz;1000 Hz;6280 Hz;10 kHz;Question 3. 3. (TCO 1) The signal is 10 sin (2 pi 1000 t + 30 degrees). The phase shift of this signal is (Points: 5) +60 degrees;+30 degrees;-30 degrees;-90 degrees;Question 4. 4. (TCO 1) The signal is 5 sin (2 pi 2000 t + 60 degrees). The voltage displayed on the DMM is (Points: 5) 5 V PP;3.535 V PP;3.535 V RMS;3.535 V PK;Question 5. 5. (TCO 1) Inductive reactance is the opposition that an inductor shows to _______. (Points: 5) alternating current;direct current;AC and DC;none of the above;Question 6. 6. (TCO 2) In an AC circuit a resistor, a reactance X C and a reactance X L are connected in series. The circuit current (Points: 5) leads the applied voltage.;lags the applied voltage.;is in phase with the voltage.;leads or lags the applied depending on the reactance that dominates in the circuit.;Question 7. 7. (TCO 2) For the following series AC circuit, the angle of the circuit impedance is;(Points: 5) 0 degrees;+90 degrees;+45 degrees;-45 degrees;Question 8. 8. (TCO 2) For the following series AC circuit, the phase angle of the circuit current is;(Points: 5) 0 degrees;+90 degrees;+45 degrees;-45 degrees;Question 9. 9. (TCO 2) For the following series AC circuit, the total circuit impedance is;(Points: 5) 100 - j 100;100 + j 100;100 - j 200;100 + j 300;Question 10. 10. (TCO 3) For the parallel AC circuit shown below, find the circuit current I S. Note that V in AC is mislabeled, it should be 10V, NOT 10 sin(? t).;(Points: 5) 0.1 + j 0.1 A;0.1 - j 0.1 A;0.1 A;j 0.2 A;Question 11. 11. (TCO 3) The total admittance for the following circuit is;Hint: Y T = G + j (B C - B L) siemens, G = 1/R siemens, B C = C siemens and B L = 1/[ L ] siemens;(Points: 5) 0.005 - j 0.005 siemens;0.005 + j 0.005 siemens;0.01 - j 0.005 siemens;0.01 + j 0.005 siemens

Paper#67538 | Written in 18-Jul-2015

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