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Algorithms Questions 2




We proved that the running time of mergesort is T(n)=n*lg(n) under the following condition;T(n) = 0 if n = 1;T(n) = 2T(n/2) + n if n > 1;1) Prove by telescoping that T(n) = cn*lg(n) + cn under the following condition;T(n) = c if n = 1;T(n) = 2T(n/2) + cn if n > 1;2) Explain why T(1)'s values above 0 versus c when n = 1 will not matter for comparing algorithms. Give an example of a hypothetical situation when you implement a search engine in terms of the search volume and execution time required to complete the search.;3) Explain why the following two versions of running time will not make a difference in terms of algorithm analysis using the asymptotic notation. Also, explain in terms of growth the condition where cn will not matter in relation to cn*lg(n).;cn*lg(n) + cn;n*lg(n)


Paper#70226 | Written in 18-Jul-2015

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